AppletTalk.com Java discussions newsgroups   Archives   FAQ   Search   Memberlist   Usergroups   Register   Profile   Log in to check your private messages   Log in  tic tac toe Goto page 1, 2  Next          AppletTalk.com Forum Index -> Java Help View previous topic :: View next topic   Author Message Michael Guest Posted: Fri Oct 21, 2005 12:25 am    Post subject: tic tac toe Hello guys, I went to see my instructor today and resolved my problem with the previous question. I know think I understand the logic of using flags. I'll review it when I have some time, just to make sure it sticks in my head. Anyways I have to make a tic tac toe game now for tomorrow. He explained to me what I ought to do. But of course I am having problems implementing it in java. First off, I think this is a basic tic tac toe game compared with others I have seen on the net. Anyways the board is labeled like this; 123 456 789 I know I have to first count the number of x's and o's. For that I will use two for loops (one for x's and one for o's). Then I need to set x equal to y. IF there even, I know it is x's turn since x starts the game. If there uneven its o's turn. My question is I know I have to count the number of x's in a for loop. But do I just assign that to a char type, then after I count both x's and o's I can compare them to see if there equal, if so its x's move otherwise its o's move. Then I need to determine whether the moves are valid or invalid. Then I need to implement a switch statement to account for all the possible outcomes of the 9 possible causes. Any suggestions are most welcome. Thanks again. I need to wrap my mind on the logic of implementing these things in java. Back to top Andrew Thompson Guest Posted: Fri Oct 21, 2005 12:36 am    Post subject: Re: tic tac toe Michael wrote: Quote: ...Any suggestions are most welcome. Thanks again. I need to wrap my mind on the logic of implementing these things in java. This might help you kick-start the process.. <http://home.earthlink.net/~patricia_shanahan/beginner.html> Back to top Michael Guest Posted: Fri Oct 21, 2005 2:00 am    Post subject: Re: tic tac toe Hello again, I read that site; good advice. I have wrote the following thus far. I realize I am comparing i to j here, but I what i really wish to do is compare if the number of x's is equal to o's. SO i order to accomplish this i would need the assignment operator = but then I can't use the if/else statement. This is somewhat puzzling me. Any suggestions? public class move { public static void main(String[] args) { String str = Stdin.readln(); char move; // count the number of X's int i = 0; while(i<= str.length()){ i++; System.out.println(i); } // count the number of O's int j = 0; while(j<= str.length()){ j++; //System.out.println(j); } if(i == j){ move = 'x'; }else{ move = 'o'; System.out.println(move); } } } "Michael" Quote: Hello guys, I went to see my instructor today and resolved my problem with the previous question. I know think I understand the logic of using flags. I'll review it when I have some time, just to make sure it sticks in my head. Anyways I have to make a tic tac toe game now for tomorrow. He explained to me what I ought to do. But of course I am having problems implementing it in java. First off, I think this is a basic tic tac toe game compared with others I have seen on the net. Anyways the board is labeled like this; 123 456 789 I know I have to first count the number of x's and o's. For that I will use two for loops (one for x's and one for o's). Then I need to set x equal to y. IF there even, I know it is x's turn since x starts the game. If there uneven its o's turn. My question is I know I have to count the number of x's in a for loop. But do I just assign that to a char type, then after I count both x's and o's I can compare them to see if there equal, if so its x's move otherwise its o's move. Then I need to determine whether the moves are valid or invalid. Then I need to implement a switch statement to account for all the possible outcomes of the 9 possible causes. Any suggestions are most welcome. Thanks again. I need to wrap my mind on the logic of implementing these things in java. Back to top Michael Guest Posted: Fri Oct 21, 2005 2:15 am    Post subject: Re: tic tac toe Question: Why is this program printing out a O, when it should be an x? Here's my code updated code. public class move { public static void main(String[] args) { String str = Stdin.readln(); boolean a = true; char move; // count the number of X's int i = 0; while(i<= str.length()){ i++; //System.out.println(i); } // count the number of O's int j = 0; while(j<= str.length()){ j++; //System.out.println(j); } a=(i%2==0 && j%2==0); if(a){ move = 'X'; }else{ move = 'O'; } System.out.println(move); } } "Michael" Quote: Hello again, I read that site; good advice. I have wrote the following thus far. I realize I am comparing i to j here, but I what i really wish to do is compare if the number of x's is equal to o's. SO i order to accomplish this i would need the assignment operator = but then I can't use the if/else statement. This is somewhat puzzling me. Any suggestions? public class move { public static void main(String[] args) { String str = Stdin.readln(); char move; // count the number of X's int i = 0; while(i<= str.length()){ i++; System.out.println(i); } // count the number of O's int j = 0; while(j<= str.length()){ j++; //System.out.println(j); } if(i == j){ move = 'x'; }else{ move = 'o'; System.out.println(move); } } } "Michael" news:EzW5f.247980$1i.229272 (AT) pd7tw2no (DOT) .. Hello guys, I went to see my instructor today and resolved my problem with the previous question. I know think I understand the logic of using flags. I'll review it when I have some time, just to make sure it sticks in my head. Anyways I have to make a tic tac toe game now for tomorrow. He explained to me what I ought to do. But of course I am having problems implementing it in java. First off, I think this is a basic tic tac toe game compared with others I have seen on the net. Anyways the board is labeled like this; 123 456 789 I know I have to first count the number of x's and o's. For that I will use two for loops (one for x's and one for o's). Then I need to set x equal to y. IF there even, I know it is x's turn since x starts the game. If there uneven its o's turn. My question is I know I have to count the number of x's in a for loop. But do I just assign that to a char type, then after I count both x's and o's I can compare them to see if there equal, if so its x's move otherwise its o's move. Then I need to determine whether the moves are valid or invalid. Then I need to implement a switch statement to account for all the possible outcomes of the 9 possible causes. Any suggestions are most welcome. Thanks again. I need to wrap my mind on the logic of implementing these things in java. Back to top Michael Guest Posted: Fri Oct 21, 2005 3:02 am    Post subject: Re: tic tac toe I got it to prints x's now. Just to implement the switch statement now I think to account for all possibilities. "Michael" <mbialowas (AT) shaw (DOT) ca> wrote Quote: Question: Why is this program printing out a O, when it should be an x? Here's my code updated code. public class move { public static void main(String[] args) { String str = Stdin.readln(); boolean a = true; char move; // count the number of X's int i = 0; while(i<= str.length()){ i++; //System.out.println(i); } // count the number of O's int j = 0; while(j<= str.length()){ j++; //System.out.println(j); } a=(i%2==0 && j%2==0); if(a){ move = 'X'; }else{ move = 'O'; } System.out.println(move); } } "Michael" news:BYX5f.244709$oW2.153239 (AT) pd7tw1no (DOT) .. Hello again, I read that site; good advice. I have wrote the following thus far. I realize I am comparing i to j here, but I what i really wish to do is compare if the number of x's is equal to o's. SO i order to accomplish this i would need the assignment operator = but then I can't use the if/else statement. This is somewhat puzzling me. Any suggestions? public class move { public static void main(String[] args) { String str = Stdin.readln(); char move; // count the number of X's int i = 0; while(i<= str.length()){ i++; System.out.println(i); } // count the number of O's int j = 0; while(j<= str.length()){ j++; //System.out.println(j); } if(i == j){ move = 'x'; }else{ move = 'o'; System.out.println(move); } } } "Michael" news:EzW5f.247980$1i.229272 (AT) pd7tw2no (DOT) .. Hello guys, I went to see my instructor today and resolved my problem with the previous question. I know think I understand the logic of using flags. I'll review it when I have some time, just to make sure it sticks in my head. Anyways I have to make a tic tac toe game now for tomorrow. He explained to me what I ought to do. But of course I am having problems implementing it in java. First off, I think this is a basic tic tac toe game compared with others I have seen on the net. Anyways the board is labeled like this; 123 456 789 I know I have to first count the number of x's and o's. For that I will use two for loops (one for x's and one for o's). Then I need to set x equal to y. IF there even, I know it is x's turn since x starts the game. If there uneven its o's turn. My question is I know I have to count the number of x's in a for loop. But do I just assign that to a char type, then after I count both x's and o's I can compare them to see if there equal, if so its x's move otherwise its o's move. Then I need to determine whether the moves are valid or invalid. Then I need to implement a switch statement to account for all the possible outcomes of the 9 possible causes. Any suggestions are most welcome. Thanks again. I need to wrap my mind on the logic of implementing these things in java. Back to top Roedy Green Guest Posted: Fri Oct 21, 2005 3:07 am    Post subject: Re: tic tac toe On Fri, 21 Oct 2005 00:25:08 GMT, "Michael" <mbialowas (AT) shaw (DOT) ca> wrote or quoted : Quote: My question is I know I have to count the number of x's in a for loop. this depends on your representation. Plausible ones include: int[3][3] index rows 0 1 2 and cols 0 1 2 0=blank, 1=X -1=O This makes checking rows and columns more mathematically obvious. int[9] then you have to figure out rows and cols using / and % -- an unnecessary complication another is char[3][3] where the position is X O or blank another is enum matrix where the three possibilities are X O and BLANK -- Canadian Mind Products, Roedy Green. http://mindprod.com Again taking new Java programming contracts. Back to top Andrew Thompson Guest Posted: Fri Oct 21, 2005 3:20 am    Post subject: Re: tic tac toe Michael wrote: ( Please trim any text you are not immediately replying to ) Quote: ...Just to implement the switch statement now I think to account for all possibilities. I am not sure what you mean here, but it sounds as though you are back on the track? Good self-help! :-) Back to top IchBin Guest Posted: Fri Oct 21, 2005 3:29 am    Post subject: Re: tic tac toe Michael wrote: Quote: public class move { public static void main(String[] args) { String str = Stdin.readln(); I do not know of a Stdin in Java. Quote: // count the number of X's int i = 0; while(i<= str.length()){ i++; Your not counting the number of X's but the total number of char in the string. Quote: //System.out.println(i); } // count the number of O's int j = 0; while(j<= str.length()){ j++; //System.out.println(j); } Again your not counting the number of O's but the total number of char in the string. -- Thanks in Advance... IchBin, Pocono Lake, Pa, USA http://weconsultants.servebeer.com/JHackerAppManager __________________________________________________________________________ 'If there is one, Knowledge is the "Fountain of Youth"' -William E. Taylor, Regular Guy (1952-) Back to top Michael Guest Posted: Fri Oct 21, 2005 4:30 am    Post subject: Re: tic tac toe almost there, I think. Just trying to figure out whether my switch statement should be of a character type or integer type. I am puzzled bc I am inputing xoxoxo***7 to get a winning combination.Any suggestions thanks again "Roedy Green" <my_email_is_posted_on_my_website (AT) munged (DOT) invalid> wrote in message news:4kmgl1hkg4o9d8accp8cv0nrsg3vbsl20b (AT) 4ax (DOT) com... Quote: On Fri, 21 Oct 2005 00:25:08 GMT, "Michael" <mbialowas (AT) shaw (DOT) ca> wrote or quoted : My question is I know I have to count the number of x's in a for loop. this depends on your representation. Plausible ones include: int[3][3] index rows 0 1 2 and cols 0 1 2 0=blank, 1=X -1=O This makes checking rows and columns more mathematically obvious. int[9] then you have to figure out rows and cols using / and % -- an unnecessary complication another is char[3][3] where the position is X O or blank another is enum matrix where the three possibilities are X O and BLANK -- Canadian Mind Products, Roedy Green. http://mindprod.com Again taking new Java programming contracts. Back to top DrMatrix Guest Posted: Sat Oct 22, 2005 12:13 am    Post subject: Re: tic tac toe In article <EzW5f.247980$1i.229272@pd7tw2no>, "Michael" <mbialowas (AT) shaw (DOT) ca> wrote: Quote: I know I have to first count the number of x's and o's. For that I will use two for loops (one for x's and one for o's). Then I need to set x equal to y. IF there even, I know it is x's turn since x starts the game. That sounds like a lot of extra trouble. Since X and O alternate. you could just define a boolean. boolean itIsXsTurn = true; // Since it starts out with X's turn After each turn, just: itIsXsTurn = !itIsXsTurn; Or Set an int variable where 0 represents X's turn and 1 represents O's int turnFlag; After each turn simply turnFlag = 1 - turnFlag; Back to top Monique Y. Mudama Guest Posted: Mon Oct 24, 2005 7:42 pm    Post subject: Re: tic tac toe On 2005-10-23, Mark Haase penned: Quote: This is a silly way to do it, Michael. For one thing, this means that X always has to go first at the beginning of the game; the O player can never make the first move. I'm pretty sure this is one of the rules of Tic Tac Toe, at least as I learned it. X goes first. -- monique Ask smart questions, get good answers: http://www.catb.org/~esr/faqs/smart-questions.html Back to top Oliver Wong Guest Posted: Tue Oct 25, 2005 8:33 pm    Post subject: Re: tic tac toe "Monique Y. Mudama" <spam (AT) bounceswoosh (DOT) org> wrote Quote: On 2005-10-23, Mark Haase penned: This is a silly way to do it, Michael. For one thing, this means that X always has to go first at the beginning of the game; the O player can never make the first move. I'm pretty sure this is one of the rules of Tic Tac Toe, at least as I learned it. X goes first. It's a rule whose presence doesn't fundamentally change the nature of the game, so it seems entirely plausible that there would be variants out there which omit or include it. Similarly, it isn't fundamental to the game that the two symbols be "X" and the other be "O". They could just as well be "+" and "0", or "1" and "2" and every strategy in the "original" variant would be exactly equally effective in the latter variant. Contrast this with a variant where a player selects a location, and a Gaussian probability cloud is generated centered on the location the player selected. The most probably event is that the location selected gets marked with the player's symbol, but there's a non-zero probability that some random other location will get marked instead (with squares nearer to your selection getting marked with higher probability). Further assume that players can overwrite each other's mark (that is, a player whose symbol is X may attempt to mark a location which is already marked with O [she may or may not succeed, due to the randomness of the tile that actually gets marked]). In this variant, there exists a strategy for the original tic tac toe game which has a different effectiveness in this game. For example, in tic tac toe, you there exists a strategy to never lose (you'll always tie or win), whereas in this variant, that same strategy may lead to a loss (especially if you're unlucky and never get the square you intended). The above, by the way, is a computer simulation of the physical game where you have a board with rotating triangular shapes. Each face of the triangular shape is marked with blank, X and O respectively, and the players are to throw bean-bags at the shapes to get them to rotate so that the locations become "marked" with the desired symbol. Because of these equivalence (or non-equivalence) of strategies, one might argue that all the variants from the first set ("X always goes first" vs "X and O take turns in going first") are the "same" game, while the variant in the second set is a "new" game. - Oliver Back to top Roedy Green Guest Posted: Tue Oct 25, 2005 10:52 pm    Post subject: Re: tic tac toe On Mon, 24 Oct 2005 13:42:03 -0600, "Monique Y. Mudama" <spam (AT) bounceswoosh (DOT) org> wrote, quoted or indirectly quoted someone who said : Quote: I'm pretty sure this is one of the rules of Tic Tac Toe, at least as I learned it. X goes first. That's the way my grandma taught it to me. Part of the game is to sucker the other naive player into letting you go first. -- Canadian Mind Products, Roedy Green. http://mindprod.com Java custom programming, consulting and coaching. Back to top Andrew Thompson Guest Posted: Tue Oct 25, 2005 11:06 pm    Post subject: Re: tic tac toe Roedy Green wrote: Quote: On Mon, 24 Oct 2005 13:42:03 -0600, "Monique Y. Mudama" [email]spam (AT) bounceswoosh (DOT) org[/email]> wrote, quoted or indirectly quoted someone who said : I'm pretty sure this is one of the rules of Tic Tac Toe, at least as I learned it. X goes first. That's the way my grandma taught it to me. Part of the game is to sucker the other naive player into letting you go first. I walked into a conference room one day, where one of the other participants had seized the opportunity (in a quiet moment) to draw a grid on the whiteboard. He marked an 'X' in one of the boxes, then thrust the marker at me, "Your turn". I drew a pyramid figure in an occupied space on the grid. "THAT'S not how you play Tic-Tic-Toe" ..he complained. "What makes you think I'm playing Tic-Tac-Toe?" I replied, before handing his marker back ..point first, and strolling off. Back to top DrMatrix Guest Posted: Wed Oct 26, 2005 1:20 am    Post subject: Re: tic tac toe In article <4odtl116pvcpo63ldmi5q6k1m5s7e5f015 (AT) 4ax (DOT) com>, Roedy Green <my_email_is_posted_on_my_website (AT) munged (DOT) invalid> wrote: Quote: On Mon, 24 Oct 2005 13:42:03 -0600, "Monique Y. Mudama" [email]spam (AT) bounceswoosh (DOT) org[/email]> wrote, quoted or indirectly quoted someone who said : I'm pretty sure this is one of the rules of Tic Tac Toe, at least as I learned it. X goes first. That's the way my grandma taught it to me. Part of the game is to sucker the other naive player into letting you go first. What difference does that make? If either player plays rationally (makes the best possible moves each turn), then the game is a win or draw for that player. If both players play rationally, the game is necessarily a draw. There is no advantage to going first. 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